【杭电ACM1000】
A + B Problem
Problem Description
Calculate A + B.
Input
Each line will contain two integers A and B. Process to end of file.
Output
For each case, output A + B in one line.
Sample Input
1 1
Sample Output
2
# include <stdio.h>
int main()
{水之镜
int a, b;
while(scanf("%d%d", &a, &b)!=EOF)
printf("%d\n", a+b);
return 0;
}
【杭电ACM1001】
嘉陵街火Sum Problem
Problem Description
Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).
In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
Input
The input will consist of a series of integers n, one integer per line.
Output
For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.
Sample Input
1 100
Sample Output
1 5050
# include <stdio.h>
int main()
{
int n, i, sum = 0;
while(scanf("%d", &n)!=EOF)
{
for(i=1; i<=n; ++i)
sum = sum + i;
printf("%d\n\n", sum);
sum = 0;
}
return 0;
}
【杭电ACM1002】
A + B Problem II
Problem Description
I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.
董家渡
天主堂Input
The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice
that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.
Output
For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.
Sample Input
2 1 2 112233445566778899 998877665544332211
Sample Output
Case 1: 1 + 2 = 3 Case 2: 112233445566778899 + 998877665544332211 = 111111*********1110
#include<stdio.h>
#include<string.h>
int shu(char a)
{
return (a-'0');
}
int main(){
char a[1000],b[1000];
int num[1001];
int n,i,j=1,al,bl,k,t;
scanf("%d",&n);
while(n--)
{
getchar();
if(j!=1)
printf("\n");
scanf("%s",a);
al=strlen(a);
scanf("%s",b);
陕西金号网
bl=strlen(b);
k=(al>bl)?al:bl;
for(i=0;i<=k;i++)
num[i]=0;
t=k;
变异系数cv
for(k;al>0&&bl>0;k--)
{
num[k]+=shu(a[--al])+shu(b[--bl]);
if(num[k]/10)
居里夫人的女儿
{
num[k-1]++;
num[k]%=10;
}
}
while(al>0)
{
num[k--]+=shu(a[--al]);
if(num[k+1]/10)
{
num[k]++;
num[k+1]%=10;
}
}
while(bl>0)
{
num[k--]+=shu(b[--bl]);
if(num[k+1]/10)
{
num[k]++;
num[k+1]%=10;
}
}
printf("Case %d:\n",j++);
printf("%s + %s = ",a,b);
for(i=0;i<=t;i++)
{
if(i==0&&num[i]==0)
i++;
printf("%d",num[i]);
}
printf("\n");
}
return 0;
}
豫公网安备41160202000603
站长QQ:729038198
关于我们
投诉建议