Java基础编程题:求s=a+aa+aaa+a的值,其中a是 ⼀个数字。
import java.util.Scanner;
//求s=a+aa+aaa+a的值,其中a是⼀个数字。
public class Main {
public static void main(String[] args) {
double sum=0;
double temp=0;
System.out.println("The equation is S=a+aa+aaa+aa..(na).a");
Scanner scanner = new Scanner(System.in);
System.out.print("Enter the a :");
int a = Int();
System.out.print("Enter the n :");
int n = Int();
System.out.printf("a is %d , n is %d .",a,n);
for(int i=0;i<n;i++) {
temp=temp+a*Math.pow(10, i);
sum=sum+temp;aaaaaaaaaaaaaaaaaa
}
System.out.println("S = "+sum);
}
}