3-7.某工程有A、B、C三个施工过程,每个施工过程均划分为三个施工段,设tA=3d,tB=2d,tC=4d。试分别计算三种施工方式的工期,并会出他们各自的施工进度计划。 答:n=3,m=3
B=K=1,N=NA+NB+NC=3/1+2/1+4/1=9个
T=(m+N-1)B=(3+9-1)×1=11d
异节拍流水:
tA>tB,Btz15AB=mtA-(m-1)×tB=3×3-(3-1)×2=5d
TB<tC,BBC=tB=2d
T=5+2+3×4=19d
非节奏流水:
(1)计算各施工过程流水节拍的累加数列
A:3,6,9
B:2,4,6
C:4,8,12
(2)将相邻两数列错位相减,得到差数列
A与B:
3,6,9
— 2,4,6
3,2,5,-6
B与C:
2,4,6
— 4,8, 12
2,0,-2,-12
(3)确定流水步距
BA,B=max{3,2,5,-6}=5
BB,C=max{2,0,-2,-12}=2
(4)计算流水施工工期
Tn=(4+4+4)d=12d
=(7+12+0+0-0)d=19d
施工过程 | 专业队号 | 施工进度/d |
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 |
A | A1 | | ① | | | | | | | | | |
A2 | | | ② | | | | | | | | |
A3 | | | | ③ | | | | | | | |
B | B1 | | | | ① | | | | | | | |
B2 | | | | | ② | | | | | | |
C | C1 | | | | | | ① | | | | | |
C2 | | | | | | | ② | | | | |
C3 | | | | | | | | ③ | | | |
C4 | | | | | | | | | ④ | | |
| | | | | | | | | | | | |
绘制异节拍流水和非节奏流水施工进度计划表
施工 过程 | 施工进度/d |
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | 16 | 17 | 18 | 19 |
A | | | | | | | | | | | | | | | | | | | |
B | | | | | | | | | | | | | | | | | | | |
C | | | | | | | | | ① | | | | | | | | | | |
| | | | | | | | | | | | | | | | | | | |
3-8.某二层现浇钢筋混凝土工程,其框架平面尺寸为15m×144m,沿长度方向每隔48米设伸缩缝一道。已知t筋=2d,t模n0492=1d,t浇=3d,层间技术间歇为2d,试组织流水施工并绘制工程进度表。 答:根据题意可组织成倍节拍流水。
(1)确定流水步距 B=K=1d
(2)计算专业工作队
N筋=2∕1个=2个,N模=1∕1个=1个,N浇=3∕1个=3个
N=N筋+ N模+ N浇=(2+1+3)=6个
(3)确定每层的施工段数
mmin=N+(Zmax+Cmax-)∕B=6个+2∕1个=8个
考虑到伸缩缝的设置 取m=9
(4)计算流水工期
T=(m×r+N-1)×B+Z=(9×2+8-1)×1+2=27d
绘制横道图
施工层数 | 施工过程 | 专业队号 | 施工进度/d |
1 | 2 | 3 | 4 | ⑤ 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | 16 | 17 | 18 | 19 | 20 | 21 | 22 | 23 | 24 | 25 | 26 | 27 |
一 | 筋 | A1 | | | | | | | | | | | | | | | | | | | | | | | | | | | |
A2 | | | | | | | | | | | | | | | | | | | | | | | | | | | |
模 | B | | | | | | | | | | | | | | | | | | | | | | | | | | | |
浇 | C1 | | | | | | | | | | | | | | | | | | | | | | | | | | | |
C2 | | | | | | | | | | | | | | | | | | | | | | | | | | | |
C3 | | | | | | | | | | | | | | | | | | | | | | | | | | | |
二 | 筋 | A1 | | | | | | | | | | | | | | | | | | | | 假牙生产 | | | | | | | |
A2 | | | | | | | | | | | | | | | | | | | | | | | | | | | |
模 | B | | | | | | | | | | | | | | | | | | | | | | | | | | | |
浇 | C1 | | | | | | | | | | | | | | | | | | | | | | | | | | | |
C2 | | | | | | | | | | | | | | | | | | | | | | | | | | | |
C3 | | | | | | | | | | | | | | | | | | | | | | | | | | | |
| | | | | | | | | | | | | | | | | | | | | | | | | | | | | |
3-9.根据表中数据,试组织流水施工并绘制施工进度表。
题3-9表
施工过程 施工段 | A | B | C | D | E |
1 | 4 | 2 | 1 | 5 | 4 |
2 | 3 | 3 | 4 | 2 | 2 |
3 | 2 | 3 | 3 | 4 | 1 |
4 | 2 | 4 | 4 | 3 | 2 |
| | | | | |
解:根据资料可知:m=4,n=5
(1)计算各施工过程流水节拍的累加数列
A:4,7,9, 11
B:2,5,8, 12
C:1,5,8, 12
D:5,7,11,14
E:4,6,7, 9
(2)将相邻两数列错位相减,得到差数列
A与B:
4,7,9,11
— 2,5,8,12
4,5,4,3,-12
B与C:
2,5,8,12
— 1,5,8,12
2,4,3,4,-12
C与D:
1,5,8,12
— 5,7,11,14
1,0,1,1,-14
D与E:
5,7,11,14
— 4,6, 7,9
5,3,5, 7,-9
(3)确定流水步距
BA,B=max{4,5,4,3,-12}=5
BB,C=max{2,4,3,4,-12}=4
BC,D=max{1,0,1,1,-14}=1
BD,E=max{5,3,5,7,-9}=7
(4)计算流水施工工期
Tn=(4+2+1+2)d=9d
=(17+9+0+0-0)d=26d
绘制流水施工进度计划表
火油草施工 过程 | 施工进度∕d |
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | 16 | 17 | 18 | 19 | 20 | 21 | 22 | 23 | 24 | 25 | 26 |
A | | | | | | | | | | | | | | | | | | | | | 硝化纤维素膜>子液位计 | | | | | |
B | | | | | | | | | | | | | | | | | | | | | | | | | | |
C | | | | | | | | | | | | | | | | | | | | | | | | | | |
D | | | | | | | | | | | | | | | | | | | | | | | | | | |
E | | | | | | | | | | | | | | | | | | | | | | | | | | |
| | | | | | | | | | | | | | | | | | | | | | | | | | |
附加题:
施工过程 | 工程量 | 单位 | 产量定额 | 人数(台数) |
挖土 | 280 | m3 | 65 | 1台 |
垫层 | 42 | m3 | — | — |
钢筋 | 10800 | kg | 450 | 2 |
浇砼 | 216 | m3 | 1.05 | 12 |
砌墙 | 330 | m3 | 1.25 | 22 |
回填 | 350 | m3 | — | — |
| | | | |
其中垫层、回填作为间歇时间处理,各预留1天时间,浇砼与砌墙工艺间歇2天。
试求:
1.计算t、T画横道图。
2.若T=18d,按固定节奏流水,则t、流水步距为多少。
解:1. 根据已知资料可知,n=4,m=4。各施工过程在每个施工段上的工程量为
Q挖=280/4=70 m3 Q垫=42/4=10.5 m3 Q钢=10800/4=2700 kg
Q浇=216/4=54 m3 Q砌=330/4=82.5 m3 Q回=350/4=87.5 m3
求各施工过程的流水节拍
t挖=70/(65*1)=1d t钢=2700/(450*2)=3d
t浇=54/(1.05*12)=3d t砌=82.5/(1.25*22)=3d
确定流水步距 B=K=1d