生物信息学
实验报告
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实验目的
了解常用的序列数据库，掌握基本的序列数据信息的查询方法。
教学基本要求
了解和熟悉NCBI 核酸和蛋白质序列数据库，可以使用BLAST进行序列搜索，解读BLAST 搜索结果，可以利用PHI-BLAST 等工具进行蛋白质序列的结构域搜索，解读蛋白质序列信息，可以在蛋白质三维数据库中查询相关结构信息并进行显示。 实验内容提要
在序列数据库中查某条基因序列（BRCA1），通过相关一系列数据库的搜索、比对与结果解释，回答以下问题：
1. 该基因的基本功能？
2. 编码的蛋白质序列是怎样的？
3. 该蛋白质有没有保守的功能结构域 (NCBI CD-search)？
4. 该蛋白质的功能是怎样的？
5. 该蛋白质的三级结构是什么？如果没有的话，和它最相似的同源物的结
构是什么样子的？给出示意图。
实验结果及结论
1. 该基因的基本功能？
This gene encodes a nuclear phosphoprotein that plays a role in maintaining genomic stability, and it also acts as a tumor suppressor. The encoded protein combines with other tumor suppressors, DNA damage sensors, and signal transducers to form a large multi-subunit protein complex known as the BRCA1-associated genome surveillance complex (BASC). This gene product associates with RNA polymerase II, and through the C-terminal domain, also interacts with histone deacetylase complexes. This protein thus plays a role in transcription, DNA repair of double-stranded breaks, and recombination. Mutations in this gene are responsible for approximately 40% of inherited breast cancers and more than 80% of inherited breast and ovarian cancers. Alternative splicing plays a role in modulating the subcellular localization and physiological function of this gene. Many alternatively spliced transcript variants, some of which are disease-associated mutations, have been described for this gene, but the full-length natures of only some of t
hese variants has been described. A related pseudogene, which is also located on chromosome 17, has been identified. [provided by RefSeq, May 2009]
2. 编码的蛋白质序列是怎样的？
[Homo sapiens]
1 mdlsalrvee vqnvinamqk ilecpiclel ikepvstkcd hifckfcmlk llnqkkgpsq
61 cplcknditk rslqestrfs qlveellkii cafqldtgle yansynfakk ennspehlkd
121 evsiiqsmgy rnrakrllqs epenpslqet slsvqlsnlg tvrtlrtkqr iqpqktsvyi
181 elgsdssedt vnkatycsvg dqellqitpq gtrdeislds akkaacefse tdvtntehhq
241 psnndlntte kraaerhpek yqgssvsnlh vepcgtntha sslqhenssl lltkdrmnve
301 kaefcnkskq pglarsqhnr wagsketcnd rrtpstekkv dlnadplcer kewnkqklpc
361 senprdtedv pwitlnssiq kvnewfsrsd ellgsddshd gesesnakva dvldvlnevd
421 eysgssekid llasdpheal ickservhsk svesniedki fgktyrkkas lpnlshvten
481 liigafvtep qiiqerpltn klkrkrrpts glhpedfikk adlavqktpe minqgtnqte
541 qngqvmnitn sghenktkgd siqneknpnp ieslekesaf ktkaepisss isnmelelni
601 hnskapkknr lrrksstrhi halelvvsrn lsppnctelq idscssseei kkkkynqmpv
661 rhsrnlqlme gkepatgakk snkpneqtsk rhdsdtfpel kltnapgsft kcsntselke
721 fvnpslpree keekletvkv snnaedpkdl mlsgervlqt ersvesssis lvpgtdygtq
781 esisllevst lgkaktepnk cvsqcaafen pkglihgcsk dnrndtegfk yplghevnhs
841 retsiemees eldaqylqnt fkvskrqsfa pfsnpgnaee ecatfsahsg slkkqspkvt
901 feceqkeenq gknesnikpv qtvnitagfp vvgqkdkpvd nakcsikggs rfclssqfrg
961 netglitpnk hgllqnpyri pplfpiksfv ktkckknlle enfeehsmsp eremgnenip
1021 stvstisrnn irenvfkeas ssninevgss tnevgssine igssdeniqa elgrnrgpkl
1081 namlrlgvlq pevykqslpg snckhpeikk qeyeevvqtv ntdfspylis dnleqpmgss
1141 hasqvcsetp ddllddgeik edtsfaendi kessavfsks vqkgelsrsp spfththlaq
1201 gyrrgakkle sseenlssed eelpcfqhll fgkvnnipsq strhstvate clsknteenl
1261 lslknslndc snqvilakas qehhlseetk csaslfssqc seledltant ntqdpfligs
1321 skqmrhqses qgvglsdkel vsddeergtg leennqeeqs mdsnlgeaas gcesetsvse
1381 dcsglssqsd ilttqqrdtm qhnliklqqe maeleavleq hgsqpsnsyp siisdssale
1441 dlrnpeqsts ekavltsqks seypisqnpe glsadkfevs adsstsknke pgversspsk
1501 cpslddrwym hscsgslqnr nypsqeelik vvdveeqqle esgphdltet sylprqdleg
1561 tpylesgisl fsddpesdps edrapesarv gnipsstsal kvpqlkvaes aqspaaahtt
1621 dtagynamee svsrekpelt astervnkrm smvvsgltpe efmlvykfar khhitltnli
1681 teetthvvmk tdaefvcert lkyflgiagg kwvvsyfwvt qsikerkmln ehdfevrgdv
1741 vngrnhqgpk raresqdrki frgleiccyg pftnmptdql ewmvqlcgas vvkelssftl
1801 gtgvhpivvv qpdawtedng fhaigqmcea pvvtrewvld svalyqcqel dtylipqiph
1861 shy
3. 该蛋白质有没有保守的功能结构域 (NCBI CD-search)？
有保守的供能结构域。
Mov34/MPN/PAD-1 family: BRCC36, a subunit of BRCA1-A complex
4. 该蛋白质的功能是怎样的？
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