Calculation Of Trunnion DESIG
N
DATA
Erection
weight WE =280000kg
Dynamic
factor KL =2
Number
of lugs nL=2
lifting
weight PL=2744000N
Trunnion
material Q345R
Minimum
specifie
d yield
stress
Fy=315MPa
Allowanc
e
stress,ben
ding
Fb =0.66~0.75Fy(取 0.66)
207.9MPa
Allowanc
e
stress,she
ar
Fs =0.4Fy
126MPa
Allowanc
e
stress,tens
ion
Ft =0.6Fy
189MPa
Trunnion
dimensio
n
e=250mm
Rn=250mm
to=45mm
W1=20mm
W2=45mm
Pad
dimensio
n
Rp=350mm
W3=20mm
Z=
π*[Rn^4-
(Rn-
to)^4]/(4*
Rn)
= 6.72E+06mm^3 2.42E+06
Lift trunnion section area
A =
π*[Rn^2-
(Rn-to)^2]
=64324.11mm^2
Vessel
vertical
Longitud
inal
ML=PL*e
= 6. Bending
stress
发泄壶in
trummion
σbv =ML / Z
=102.03MPa Since Fb
≥ σbv,
the
trunnion
is
adequate.
Maxium
tensile
stress
=42.66MPa
stress
σ1 =
(σbv^2+3*
τ1^2)^0.5
=125.97MPa≤0.7*Ft=132.30MPa
透气盖The trunion is adequate
Check
welds
Section
modnlus
of weld
Sw=πR n^2
=196350mm^2 Shear
stress
in weld
due to
bending
moment
fs=ML/Sw
=3493.77N/mm
W=fs/Fs
=27.73mm Since W2
≥ W, the
trunnion
is
adequate.
Section
modnlus
of pad
weld
Spw=2π*Rp
=2199mm Shear
stress
in pad
weld due
to
bending
moment
fps=PL/Spw
=1247.77N/mm
=9.90mm Since W3
≥ Wp,
the
trunnion
is
adequate.
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