signature今日头条php实现,今日头条_signature分析


2023年12月21日发(作者:糊涂的反义词)

y = l}}for (var h, y, d, g, v = [], x = 0; ; )switch (g = deAt(b++) - 32) {case 1:u(!v[--x]);break;case 4:v[x++] = f();break;case 5:u(function(e) {var a = 0, r = ;return function() {var c = a < r;return c && u(e[a++]),c}}(v[--x]));break;case 6:y = v[--x],u(v[--x](y));break;case 8:if (g = deAt(b++) - 32,l(),b += g,g = deAt(b++) - 32,y === c)b += g;else if (y !== l)

return y;break;case 9:v[x++] = c;break;case 10:u(s(v[--x]));break;case 11:y = v[--x],u(v[--x] + y);break;case 12:for (y = f(),d = [],g = 0; g < ; g++)d[g] = deAt(g) ^ g + ;u((null, d));break;case 13:y = v[--x],h = delete v[--x][y];break;case 14:v[x++] = deAt(b++) - 32;break;case 59:u((g = deAt(b++) - 32) ? (y = x,(x -= g, y)) : []);break;case 61:u(v[--x][deAt(b++) - 32]);break;case 62:

g = v[--x],k[0] = 65599 * k[0] + k[1].charCodeAt(g) >>> 0;break;case 65:h = v[--x],y = v[--x],v[--x][y] = h;break;case 66:u(e(t[b++], v[--x], v[--x]));break;case 67:y = v[--x],d = v[--x],u((g = v[--x]).x === c ? r(g.y, y, k) : (d, y));break;case 68:u(e((g = t[b++]) < "f()) : g + g, v[--x], v[--x]));break;case 70:u(!1);break;case 71:v[x++] = n;break;case 72:v[x++] = +f();break;case 73:u(parseInt(f(), 36));break;case 75:if (v[--x]) {

b++;break}case 74:g = deAt(b++) - 32 << 16 >> 16,b += g;break;case 76:u(k[deAt(b++) - 32]);break;case 77:y = v[--x],u(v[--x][y]);break;case 78:g = deAt(b++) - 32,u(a(v, x -= g + 1, g));break;case 79:g = deAt(b++) - 32,u(k["$" + g]);break;case 81:h = v[--x],v[--x][f()] = h;break;case 82:u(v[--x][f()]);break;case 83:h = v[--x],k[deAt(b++) - 32] = h;break;case 84:

v[x++] = !0;break;case 85:v[x++] = void 0;break;case 86:u(v[x - 1]);break;case 88:h = v[--x],y = v[--x],v[x++] = h,v[x++] = y;break;case 89:u(function() {function e() {return r(e.y, arguments, k)}return e.y = f(),e.x = c,e}());break;case 90:v[x++] = null;break;case 91:v[x++] = h;break;case 93:h = v[--x];break;case 0:

return v[--x];default:u((g << 16 >> 16) - 16)}}var n = this, t = on, s = || function(e) {var a = {}, r = 0;for (var c in e)a[r++] = c;return = r,a}, b = {}, k = {};r(arCode(103,114,36,68,97,116,101,110,32,1048,98,47,115,33,108,32,121,850,121,313,103,44,40,108,10[TAC = {}]);}asd();function test(){return ("335088197840");}


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